You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question
42 EXAMPLE
Problems using Newton's Law of cooling
A body cools from 70°C to 50°C in 5 minutes. Temperature of
surroundings is 20° C. Its temperature after next 10 minutes is
Newton's cooling law-=-k(8-6)
putting the given values of the situation in the formula we get:-
(70 - 50)
dt
--k(70 - 20)
20
k(50)
2
25
now, cooling body at 50°C for 10 min
let temperature after 10 min be T
(50-2) (50-20)
25
(50-T)12
10
10
50-T-24
T- 5024
T=26) C
Open in App
Solution
Verified by Toppr
Was this answer helpful?
3
Similar Questions
Q1
A body cools from 70oC to 50oC in 5 minutes. The temperature of the surroundings is 20oC. Its temperature after the next 10 minutes is:
View Solution
Q2
A body cools from 70oC to 50oC in 5 minutes. Temperature of surroundings is 20oC. Its temperature after next 10 minutes is
View Solution
Q3
A body initially at 60oC cools to 50oC in 10min. What will be its temperature the end of next 10min, if the room temperature is 20oC. Assume Newtons law of cooling.
View Solution
Q4
A body cools from 60∘C to 50∘C in 10 minutes. If the room temperature is 25∘C and assuming Newton' s law of cooling to hold good, the temperature of the body at the end of the next 10 minutes will be
View Solution
Q5
A body cools from 60∘C to 50∘C in 10 min. If the room temperature is 25∘C and assuming Newton's cooling law holds good, the temperature of the body at the end of next 10 minutes is :