A uniform metre rule of weight 2-0N is pivoted the 60cm mark- A 4-0N load is suspended from one end- causing the rule to rotate about the pivot-At the instant when the rule is horizontal- what is the resultant moment about the pivot-

Question

Toppr Admin · Accepted Answer

Correct option is B- -1-4-NmTorque due to load -4N-times40cm-1-6Nm-Torque due to weight of the rule -2N-times10cm-0-2Nm-Both are in opposite to each other so net torque -1-6-0-2-1-4Nm-

A uniform metre rule of weight $$2.0$$N is pivoted at the $$60$$cm mark. A $$4.0$$N load is suspended from one end, causing the rule to rotate about the pivot.
At the instant when the rule is horizontal, what is the resultant moment about the pivot?

Correct option is B. $$1.4$$Nm
Torque due to load $$=4N\times40cm=1.6Nm$$
Torque due to weight of the rule $$=2N\times10cm=0.2Nm$$
Both are in opposite to each other so net torque $$=1.6-0.2=1.4Nm$$

A uniform metre rule of weight $$2.0$$N is pivoted at the $$60$$cm mark. A $$4.0$$N load is suspended from one end, causing the rule to rotate about the pivot.At the instant when the rule is horizontal, what is the resultant moment about the pivot?

Correct option is B. $$1.4$$NmTorque due to load $$=4N\times40cm=1.6Nm$$Torque due to weight of the rule $$=2N\times10cm=0.2Nm$$Both are in opposite to each other so net torque $$=1.6-0.2=1.4Nm$$

A uniform metre rule of weight $$2.0$$N is pivoted at the $$60$$cm mark. A $$4.0$$N load is suspended from one end, causing the rule to rotate about the pivot.
At the instant when the rule is horizontal, what is the resultant moment about the pivot?

Correct option is B. $$1.4$$Nm
Torque due to load $$=4N\times40cm=1.6Nm$$
Torque due to weight of the rule $$=2N\times10cm=0.2Nm$$
Both are in opposite to each other so net torque $$=1.6-0.2=1.4Nm$$