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Standard XII
Physics
Question
Figure shows three circular arcs, each of radius
R
and total change as indicated. The net electric potential at the center of curvature is :-
Q
4
π
ϵ
0
R
Q
2
π
ϵ
0
R
2
Q
π
ϵ
0
R
Q
π
ϵ
0
R
A
Q
2
π
ϵ
0
R
B
Q
4
π
ϵ
0
R
C
2
Q
π
ϵ
0
R
D
Q
π
ϵ
0
R
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Solution
Verified by Toppr
The potential at centre
V
=
V
1
+
V
2
+
V
3
=
K
Q
R
+
K
(
−
2
Q
)
R
+
K
(
3
Q
)
R
=
2
k
Q
R
=
2
Q
4
Π
ε
0
R
=
Q
2
Π
ε
0
R
Hence (A) option is correct
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