In Millikan’s experiment, the slope of v versus Vo graph was found to be 4.125×10−15Vs. Given e=1.6×10−19C, the value of Planck’s constant is
6.2×10−34Js
6.4×10−34Js
4.125×10−34Js
6.6×10−34Js
A
6.4×10−34Js
B
4.125×10−34Js
C
6.6×10−34Js
D
6.2×10−34Js
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Solution
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Using Vo=he−ϕ
Slope of the graph is equal to he
Slope of the graph =4.125×10−15Vs
Given : e=1.6×10−19C
Value of Planck's constant h=e×slope
∴h=1.6×10−19×4.125×10−15=6.6×10−34Js
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