Suppose A is twice as good a workman as B and together they can finish a job in 24 days. How many days A alone takes to finish the job?
A is twice a good workman as B
∴B=2A
It is given that A and B together can finish the job in 24 days.
∴1A+1B=124
Substituting B=2A we get
∴1A+12A=124
⇒2+12A=124 Taking LCM
⇒32A=124
Cross multiplying we get,
⇒3∗24=2A
⇒A=722
⇒A=36
Therefore A alone can finish the work in 36 days.