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Standard XII
Physics
Dimensional Analysis
Question
The dimensions of specific resistance are:
[
M
L
3
T
−
2
A
−
1
]
[
M
L
3
T
−
3
A
−
2
]
[
M
L
−
2
A
−
1
]
[
M
L
2
T
−
2
A
−
2
]
A
[
M
L
2
T
−
2
A
−
2
]
B
[
M
L
3
T
−
3
A
−
2
]
C
[
M
L
3
T
−
2
A
−
1
]
D
[
M
L
−
2
A
−
1
]
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Solution
Verified by Toppr
The correct option is
B
[
M
L
3
T
−
3
A
−
2
]
Resistance of a substance=
R
=
ρ
l
A
⟹
ρ
=
R
A
l
=
V
I
A
l
Dimension of
V
is
[
M
L
2
T
−
3
A
−
1
]
Dimension of
I
is
[
A
]
Dimension of
A
is
[
L
2
]
Dimenstion of
l
is
[
L
]
Thus dimension of
ρ
is
[
M
L
3
T
−
3
A
−
2
]
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3
Similar Questions
Q1
Match the following two columns:
Column I
Column II
A.
Electrical resistance
1.
[
M
L
3
T
−
3
A
−
2
]
B.
Electrical potential
2.
[
M
L
2
T
−
3
A
−
2
]
C.
Specific resistance
3.
[
M
L
2
T
−
3
A
−
1
]
D.
Specific conductance
4.
None of these
View Solution
Q2
Match the Column I with Column II.
Column I
(Physical quantity)
Column II
(Dimensional formula)
(A)
Premittivity of free space
(p)
[
M
0
L
0
T
−
1
]
(B)
Radiant flux
(q)
[
M
L
3
T
−
3
A
−
2
]
(C)
Resistivity
(r)
[
M
L
2
T
−
3
]
(D)
Hubble constant
(s)
[
M
−
1
L
−
3
T
4
A
2
]
View Solution
Q3
Match the following:
Table-1 Table-2
(
A
)
L
(
P
)
[
M
0
L
0
T
−
2
A
0
]
(
B
)
Magnetic flux
(
Q
)
[
M
L
2
T
−
2
A
−
1
]
(
C
)
L
C
(
R
)
[
M
L
2
T
−
2
A
−
2
]
(
D
)
C
R
2
(
S
)
None
View Solution
Q4
Evaluate :
(
3
a
−
1
2
)
(
3
a
−
1
2
)
View Solution
Q5
Factorize :
3
a
2
−
1
−
2
a
View Solution