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Multi-Electron Configurations and Orbital Diagrams

Question

The electronic configuration of $M n^{+ 2}$ is:
$[A r] 3 d^{5} 4 s^{0}$
$[K r] 4 d^{5} 4 s^{0}$
$[A r] 3 d^{4} 4 s^{1}$
$[A r] 3 d^{3} 4 s^{2}$

A

[K r] 4 d^{5} 4 s^{0}

B

[A r] 3 d^{5} 4 s^{0}

C

[A r] 3 d^{3} 4 s^{2}

D

[A r] 3 d^{4} 4 s^{1}

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Solution

Verified by Toppr

Mn has Atomic number = 25 ,
So electronic configuration of $M n^{+ 2}$ will be $[A r] 3 d^{5} 4 s^{0}$

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Similar Questions

Q1

If the electronic configuration of a transition metal is

[A r] 3 d^{3} 4 s^{2}

, then its possible oxidation states are:

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Q2

The electronic configuration of

M n^{+ 2}

is:

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Q3

Read below given tabular form and answer the questions.

Element	Electronic configuration	Element	Electronic configuration
$H e$	$1 s^{2}$	$K r$	$4 s^{2} 4 p^{6}$
$N e$	$2 s^{2} 2 p^{6}$	$X e$	$5 s^{2} 5 p^{6}$
$A r$	$3 s^{2} 3 p^{6}$	$R n$	$6 s^{2} 6 p^{6}$

Which element has electronic configuration as

n s^{2}

formula?

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Q4

Electronic configuration

[K r] 4 d^{10}

belongs to:

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Q5

An ion has electronic configuration

[K r] 4 d^{4}

placed in group 6 in the modern periodic table. The ion is:

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