A ray of light is incident normally on one of the faces of a prism of apex angle 30o and refractive index √2. The angle of deviation of the ray is
15o
0o
22.5o
12.5o
A
15o
B
0o
C
12.5o
D
22.5o
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Solution
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Using geometry in the figure, we get incident angle at prism face AC i=30o
Snell's law at P : μsini=1×sinr
∴√2×sin30o=sinr⟹r=sin−1(1√2)=45o
Thus deviation of ray: δ=r−i=45o−30o=15o
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