An electric dipole of moment 'p' is placed in an electric field of intensity 'E'. The dipole acquires a position such that the axis of the dipole makes an angle 0 with the direction of the field. Assuming that the potential energy of the dipole to be zero when θ=900, the torque and the potential energy of the dipole will respectively be:
pEsinθ,2pEcosθ
pEcosθ,−pEsinθ
pEsinθ,−pEcosθ
pEsinθ,−2pEcosθ
A
pEsinθ,−pEcosθ
B
pEsinθ,2pEcosθ
C
pEsinθ,−2pEcosθ
D
pEcosθ,−pEsinθ
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Solution
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The correct option is CpEsinθ,−pEcosθ
Potential energy of the dipole
U=−∫TdB
=−∫θπ/2PEsinθdθ
=PE(cosθ−0)=−PEcosθ
and potential energy =PEsinθ.
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