If g on the surface of the Earth is 9.8ms−2, its value at a height of 6400km is: (Radius of the Earth =6400km)
4.9ms−2
19.6ms−2
9.8ms−2
2.45ms−2
A
19.6ms−2
B
4.9ms−2
C
9.8ms−2
D
2.45ms−2
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Solution
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The expression for g is given by: gR=GMR2 The value of g changes according to gh=GM(R+h)2 Therefore, ghgR=R2(R+h)2 Here, h=R So, ghgR=(RR+h)2 ⇒ghgR=(RR+R)2 ⇒gh=gR×14=9.8×0.25=2.45m/s2
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