If the radius of the base of a right circular cylinder is halved, keeping the height same, what is the ratio of the volume of the reduced cylinder to that of the original.
1:3
1:7
1:5
1:4
A
1:3
B
1:4
C
1:7
D
1:5
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Solution
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circular cylinder's radius=r height=h keeping the height same, radius is halved radius of new circular cylinder=r/2 So, ratio of volume = volume of reduced cylinder/volume of original cylinder Ratio=Πr/22h/Π(r)2h Ratio=1/4
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