The electrostatic potential energy of two point charges, 1μC each, placed 1 meter apart in air is?
9×103J
9×109J
9×10−3J
9×10−3eV
A
9×103J
B
9×109J
C
9×10−3J
D
9×10−3eV
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Solution
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Step 1: Formula of Potential energy
Electrostatic potential energy is given by U between two charges placed at a separtion r is given by
⇒U=kq1q2r
Step 2: Calculations
Putting values, k=9×109N.m2C2,
q2=q1=1μC=1×10−6C,
r=1m
⇒U=9×109×1×10−6×1×10−61=9×10−3J
Hence, correct option is C.
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