What is the de Broglie wavelength of the electron accelerated through a potential difference of 100 Volt?
12.27 ˚A
1.227 ˚A
0.1227 ˚A
0.001227 ˚A
A
0.001227 ˚A
B
12.27 ˚A
C
1.227 ˚A
D
0.1227 ˚A
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Solution
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Given : V=100 volts
de-Broglie wavelength of electron λ=h√2meV
∴λ=6.6×10−34√2(9.1×10−31)(1.6×10−19)(100)
Or λ=6.6×10−345.4×10−10 m
⟹λ=1.227×10−10m=1.227˚A
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