The correct options are
B The volume of H2C2O4 required is 80 mL.
C The normality of KAl(OH)2CO3 is 0.4 N.
D It is a redox reaction.
The reaction between KAl(OH)2CO3 and H2C2O4 is an acid -base titration.
Milliequivalents of KAl(OH)2CO3 = Milliequivalents of H2C2O4
100 ×0.2×4=14×2×V
VH2C2O4=160 mL
NKAl(OH)2CO3=0.2×4=0.8 N