As shown in the figure, O is the centre of hexagon ABCDEF of each side 8cm. As it is a regular hexagon OAB, OBC etc are equilateral triangles.
∴ OA=OB=OC=OD=OD=OF=8cm=8×10−2m
Step 2 : Calculating Potential
Since, Distances of each charge from O is same, therefore Potential due to to all the charges at O would be same.
& Potential being a scalar quantity will be added at O due to each charge
∴VO=VA+VB+VC+VD+VE+VF=6VA
⇒VO=6×q4πε0r=6×9×109×(4×10−6C)8×10−2m=2.7×106V