A microscopic particle of mass 10-12- kg is moving with a velocity of 10-2- m-s- Then the de-Broglie wavelength associated with the particle is6-6times 10-24-m6-6times 10-34-m3-3times 10-24-m0

Question

Toppr Admin · Accepted Answer

-x3BB-hm-x3BD-6-6-xD7-10-x2212-3410-x2212-12-xD7-102-6-6-xD7-10-x2212-24mSo- the answer is option -A-

A microscopic particle of mass $10^{- 12}$ kg is moving with a velocity of $10^{2}$ m/s. Then the de-Broglie wavelength associated with the particle is
$6.6 \times 10^{- 24} m$
$6.6 \times 10^{34} m$
$3.3 \times 10^{24} m$
$0$

$λ = \frac{h}{m ν}$

$= \frac{6.6 \times 10^{- 34}}{10^{- 12} \times 10^{2}}$

$= 6.6 \times 10^{- 24} m$
So, the answer is option (A).

A microscopic particle of mass 10−12 kg is moving with a velocity of 102 m/s. Then the de-Broglie wavelength associated with the particle is6.6×10−24m6.6×1034m3.3×1024m0

λ=hmν=6.6×10−3410−12×102=6.6×10−24mSo, the answer is option (A).

A microscopic particle of mass $10^{- 12}$ kg is moving with a velocity of $10^{2}$ m/s. Then the de-Broglie wavelength associated with the particle is
$6.6 \times 10^{- 24} m$
$6.6 \times 10^{34} m$
$3.3 \times 10^{24} m$
$0$

$λ = \frac{h}{m ν}$

$= \frac{6.6 \times 10^{- 34}}{10^{- 12} \times 10^{2}}$

$= 6.6 \times 10^{- 24} m$
So, the answer is option (A).