A particle of specific charge qm=πCkg−1 is projected from the origin toward positive x−axis with a velocity of 10ms−1 in a uniform magnetic field →B=−2^kT. The velocity →v of particle after time t=112s will be (in ms−1)
5[√3^i−^j]
5[^i+√3^j]
5[√3^i+^j]
5[^i+^j]
A
5[√3^i+^j]
B
5[√3^i−^j]
C
5[^i+√3^j]
D
5[^i+^j]
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Solution
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Time period T=2πmqB=2πqmB=2ππ×2=1s
Since the particle will be at point P after time t=112=T12s , it is deviated by an angle θ=2π12=300
A particle of specific charge qm=πCkg−1 is projected from the origin toward positive x−axis with a velocity of 10ms−1 in a uniform magnetic field →B=−2^kT. The velocity →v of particle after time t=112s will be (in ms−1)
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Q2
A charged particle of specific charge α is released from origin at time t=0 with velocity →v=v0(^i+^j) in magnetic field →B=B0^i. The coordinate of the particle at time t=πB0α will be
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Q3
Let →a=^i+^j+^k, →b=^i−^j+^k and →c=^i−^j−^k be three vectors. A vector →v in the plane of →a and →b, whose projection on →c is 1√3, is given by
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Q4
A charged particle of specific charge, α=(qm) is released at origin at t=0 with velocity v=v0(^i+^j) in a uniform magnetic field B=B0^i. Coordinates of particle at time t=πB0α are:
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Q5
A charged particle of specific charge α is released from origin at time t=0 with velocity →v=v0(^i+^j) in a uniform magnetic field →B=B0^i. Find the coordinates of the particle at time t=πB0α are [α=(q/m)]