A proton and an electron are accelerated by the same potential difference. Let $λ_{c}$ and $λ_{p}$ denote the de Broglie wavelengths of the electron and the proton respectively.
$λ_{c} = λ_{p}$
$λ_{c} > λ_{p}$
$λ_{c} < λ_{p}$
The relation between $λ_{c}$ and $λ_{p}$ depends on the accelerating potential difference.

Question

A proton and an electron are accelerated by the same potential difference. Let $λ_{c}$ and $λ_{p}$ denote the de Broglie wavelengths of the electron and the proton respectively.
$λ_{c} = λ_{p}$
$λ_{c} > λ_{p}$
$λ_{c} < λ_{p}$
The relation between $λ_{c}$ and $λ_{p}$ depends on the accelerating potential difference.

Toppr Admin · Accepted Answer

De Broglie wavelength of a particle of mass m moving under a potential V is given my-x3BB-h-x221A-2meV-xA0-So it is clear that de Broglie wavelength is inversely proportional to the square root of the mass of the material- Now mass of electron is less that the mass of the proton so de Broglie wavelength of electron will be greater than that of proton- So- the answer is option -C-

A proton and an electron are accelerated by the same potential difference. Let λc and λp denote the de Broglie wavelengths of the electron and the proton respectively.λc=λpλc>λpλc<λpThe relation between λc and λp depends on the accelerating potential difference.