ABC is an isosceles triangle in which altitudes BE and CF are drawn to equal sides AC and AB respectively. Show that ΔABE≅ΔACF
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Solution
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In △ABE and △ACF, we have
∠AEB=∠AFC [Since Each =90o]
∠BAE=∠CAF [Common]
and AB=AC [Given]
∴ By AAS criterion of congruence, we have
△ABE≅△ACF
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ABC is an isosceles triangle in which altitudes BE and CF are drawn to equal sides AC and AB respectively. Show that ΔABE≅ΔACF
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