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An electron in the hydrogen atom jumps from excited state n to the ground state. The wavelength so emitted illuminates a photosensitive material having work function $2.75 e V$ . If the stopping potential of the photoelectron is $10 V$ , then the value of $n$ is :-
$2$
$3$
$4$
$5$

5

3

4

2

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Solution

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$E_{P h} = K . E_{m a x} + W$
$= e V_{0} + W = 10 + 2.75 = 12.75 e V$

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An electron in the hydrogen atom jumps from excited state n to the ground state. The wavelength so emitted illuminates a photosensitive material having work function $2.75 e V$ . If the stopping potential of the photoelectron is $10 V$ , then the value of $n$ is :-
$2$
$3$
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$E_{P h} = K . E_{m a x} + W$
$= e V_{0} + W = 10 + 2.75 = 12.75 e V$