An X-ray tube is being operated 10 kV- The maximum frequency of X-rays produced is- -h-6-6times 10-34-m-2kg-s-2-4times 10-20-Hz2-4times 10-11-Hz2-4times 10-19-Hz2-4times 10-18-Hz

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P-d-xD7-e-xA0-xA0-energy-xA0-xA0-h-xA0-x3BD-10-xD7-103-xD7-1-6-xD7-10-x2212-19-xA0-6-6-xD7-10-x2212-34-xA0-x3BD-x3BD-xA0-104-xD7-1-6-xD7-10-x2212-196-6-xD7-10-x2212-34-xA0-2-4-xD7-1018-xA0-Hz

An X-ray tube is being operated at $10 k V$ . The maximum frequency of X-rays produced is: $(h = 6.6 \times 10^{- 34} m^{2} k g / s)$
$2.4 \times 10^{20} H z$
$2.4 \times 10^{11} H z$
$2.4 \times 10^{19} H z$
$2.4 \times 10^{18} H z$

$p . d . \times e = e n e r g y = h ν$

$10 \times 10^{3} \times 1.6 \times 10^{- 19} = 6.6 \times 10^{- 34} ν$

$ν = \frac{10^{4} \times 1.6 \times 10^{- 19}}{6.6 \times 10^{- 34}}$

$= 2.4 \times 10^{18} H z$

An X-ray tube is being operated at 10 kV. The maximum frequency of X-rays produced is: (h=6.6×10−34m2kg/s)2.4×1020Hz2.4×1011Hz2.4×1019Hz2.4×1018Hz

p.d.×e = energy = h ν10×103×1.6×10−19= 6.6×10−34 νν= 104×1.6×10−196.6×10−34= 2.4×1018 Hz

An X-ray tube is being operated at $10 k V$ . The maximum frequency of X-rays produced is: $(h = 6.6 \times 10^{- 34} m^{2} k g / s)$
$2.4 \times 10^{20} H z$
$2.4 \times 10^{11} H z$
$2.4 \times 10^{19} H z$
$2.4 \times 10^{18} H z$

$p . d . \times e = e n e r g y = h ν$

$10 \times 10^{3} \times 1.6 \times 10^{- 19} = 6.6 \times 10^{- 34} ν$

$ν = \frac{10^{4} \times 1.6 \times 10^{- 19}}{6.6 \times 10^{- 34}}$

$= 2.4 \times 10^{18} H z$