Assuming that the work of the surface can be neglected- the relation between the de-Broglie wavelength -lambda- of the electrons emitted to the energy -E-upsilon- of the incident photons- Draw the nature of the graph lambda as a of -E-upsilon-

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Since work function is neglected- hence all the energy imparted by photons to electrons-xA0-comes as kinetic energy- Let the kinetic energy of electrons be-xA0-K-12mv2-Eorv-x221A-2Emormv-x221A-2EmThus-x3BB-hmv-h-x221A-2Em

Assuming that the work function of the surface can be neglected, find the relation between the de-Broglie wavelength ( $λ$ ) of the electrons emitted to the energy ( $E_{υ}$ ) of the incident photons. Draw the nature of the graph for $λ$ as a function of ( $E_{υ}$ ).

Since work function is neglected, hence all the energy imparted by photons to electrons comes as kinetic energy. Let the kinetic energy of electrons be
$K = \frac{1}{2} m v^{2} = E o r v = \sqrt{\frac{2 E}{m}} o r m v = \sqrt{2 E m} T h u s, λ = \frac{h}{m v} = \frac{h}{\sqrt{2 E m}}$

Assuming that the work function of the surface can be neglected, find the relation between the de-Broglie wavelength (λ) of the electrons emitted to the energy (Eυ) of the incident photons. Draw the nature of the graph for λ as a function of (Eυ).

Since work function is neglected, hence all the energy imparted by photons to electrons comes as kinetic energy. Let the kinetic energy of electrons be K=12mv2=Eorv=√2Emormv=√2EmThus,λ=hmv=h√2Em

Assuming that the work function of the surface can be neglected, find the relation between the de-Broglie wavelength ( $λ$ ) of the electrons emitted to the energy ( $E_{υ}$ ) of the incident photons. Draw the nature of the graph for $λ$ as a function of ( $E_{υ}$ ).

Since work function is neglected, hence all the energy imparted by photons to electrons comes as kinetic energy. Let the kinetic energy of electrons be
$K = \frac{1}{2} m v^{2} = E o r v = \sqrt{\frac{2 E}{m}} o r m v = \sqrt{2 E m} T h u s, λ = \frac{h}{m v} = \frac{h}{\sqrt{2 E m}}$