Figure shows K-alpha- - K-beta- X-rays along with continuous X-ray- Find the energy of L-alpha- X-ray- -Use hc - 12420 evdot-A- -6-21 J6-21 KeV6-21 MeV13-26 KeV

Question

Figure shows K-alpha- - K-beta- X-rays along with continuous X-ray- Find the energy of L-alpha-  X-ray- -Use hc - 12420 evdot-A- -6-21 J6-21 KeV6-21 MeV13-26 KeV

Toppr Admin · Accepted Answer

EL-x3B1-EK-x3B2-x2212-EK-x3B1-12420-11-x2212-12-124202-6210eV-6-21KeVSo- the answer is option -A-

Figure shows $K_{α}$ & $K_{β}$ X-rays along with continuous $X - r a y .$ Find the energy of $L_{α} X - r a y .$ (Use hc $=$ 12420 $e v ˙ A$ )

$6.21 J$
$6.21 K e V$
$6.21 M e V$
$13.26 K e V$

$E_{L_{α}} = E_{K β} - E_{K α} = 12420 (\frac{1}{1} - \frac{1}{2})$

$= \frac{12420}{2} = 6210 e V = 6.21 K e V$

So, the answer is option (A).

Figure shows Kα & Kβ X-rays along with continuous X−ray. Find the energy of Lα X−ray. (Use hc = 12420 ev˙A )6.21J6.21KeV6.21MeV13.26KeV

ELα=EKβ−EKα=12420(11−12)=124202=6210eV=6.21KeVSo, the answer is option (A).

Figure shows $K_{α}$ & $K_{β}$ X-rays along with continuous $X - r a y .$ Find the energy of $L_{α} X - r a y .$ (Use hc $=$ 12420 $e v ˙ A$ )

$6.21 J$
$6.21 K e V$
$6.21 M e V$
$13.26 K e V$

$E_{L_{α}} = E_{K β} - E_{K α} = 12420 (\frac{1}{1} - \frac{1}{2})$

$= \frac{12420}{2} = 6210 e V = 6.21 K e V$

So, the answer is option (A).