Find force on semicircular ring due to point charge q.
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Solution
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Consider an element at an angle θ charge dq=λRdθ
∴ Force on charge dq,df=KqdqR2
=KqλRdθR2
Due to symmetry of the system we see Fx gets cancelled
∴∫dfy=KgλR∫π0sinθdθ
=KqλR[−cosθ]π0
F=2KqλR
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