Find the maximum kinetic energy of electrons ejected from a certain material the material-s work is 2-3 mathrm-eV- and the frequency of the incident radiation is 3-0 times 10-15- mathrm-Hz-

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Toppr Admin · Accepted Answer

We use Eq- 38-5 to find the maximum kinetic energy of the ejected electrons-K-max -h f-Phi-left-4-14 -times 10-15- -mathrm-eV- -cdot -mathrm-s-right-left-3-0 -times 10-15- -mathrm-Hz-right-2-3 -mathrm-eV-10 -mathrm-eV-

Find the maximum kinetic energy of electrons ejected from a certain material if the material's work function is $$2.3 \mathrm{eV}$$ and the frequency of the incident radiation is $$3.0 \times 10^{15} \mathrm{Hz}$$

We use Eq. 38-5 to find the maximum kinetic energy of the ejected electrons:
$$K_{\max }=h f-\Phi=\left(4.14 \times 10^{-15} \mathrm{eV} \cdot \mathrm{s}\right)\left(3.0 \times 10^{15} \mathrm{Hz}\right)-2.3 \mathrm{eV}=10 \mathrm{eV}\\$$

Find the maximum kinetic energy of electrons ejected from a certain material if the material's work function is $$2.3 \mathrm{eV}$$ and the frequency of the incident radiation is $$3.0 \times 10^{15} \mathrm{Hz}$$

We use Eq. 38-5 to find the maximum kinetic energy of the ejected electrons:$$K_{\max }=h f-\Phi=\left(4.14 \times 10^{-15} \mathrm{eV} \cdot \mathrm{s}\right)\left(3.0 \times 10^{15} \mathrm{Hz}\right)-2.3 \mathrm{eV}=10 \mathrm{eV}\\$$

We use Eq. 38-5 to find the maximum kinetic energy of the ejected electrons:
$$K_{\max }=h f-\Phi=\left(4.14 \times 10^{-15} \mathrm{eV} \cdot \mathrm{s}\right)\left(3.0 \times 10^{15} \mathrm{Hz}\right)-2.3 \mathrm{eV}=10 \mathrm{eV}\\$$