Find the minimum wavelength of X-ray produced if 10 kV potential difference is applied across the anode and cathode of the tube.

12.4 A $^{\circ}$
12.4 nm
1.24 nm
1.24 A $^{\circ}$

Question

Find the minimum wavelength of X-ray produced 10 kV potential difference is applied across the anode and cathode of the tube-12-4 A-circ-12-4 nm1-24 nm1-24 A-circ-

Toppr Admin · Accepted Answer

If electrons are accelerated to a velocity $v$ by a potential difference V and then allowed to collide with a metal target, the maximum frequency of the X-rays emitted is given by the equation:
$m v^{2} = e V = h ν$

or, $λ_{m i n} = \frac{1240}{10^{3}} * 10^{- 9} = 124 n m = 12.4 A^{\circ}$

So, the answer is option (D).

Find the minimum wavelength of X-ray produced if 10 kV potential difference is applied across the anode and cathode of the tube.12.4 A∘12.4 nm1.24 nm1.24 A∘

If electrons are accelerated to a velocity v by a potential difference V and then allowed to collide with a metal target, the maximum frequency of the X-rays emitted is given by the equation:mv2=eV=hνor, λmin=1240103∗10−9=124nm=12.4A∘So, the answer is option (D).

Find the minimum wavelength of X-ray produced if 10 kV potential difference is applied across the anode and cathode of the tube.

12.4 A $^{\circ}$
12.4 nm
1.24 nm
1.24 A $^{\circ}$