If A= 60∘ and B= 30∘, find the value of (sinAcosB+cosAsinB)2+(cosAcosB−sinAsinB)2.
(sinAcosB+cosAsinB)2+(cosAcosB−sinAsinB)2When, A=60∘ and B=30∘=(sin600cos300+cos600sin300)2+(cos600cos300−sin600sin300)2
=(√32×√32+12×12)2+(12×√32−√32×12)2
=(34+14)2
=12=1