If electron is having a wavelength of 100 $A^{0}$ , then momentum is $(g m c m s^{- 1})$ units
$6.6 \times 10^{- 29}$
$6.6 \times 10^{- 32}$
$6.6 \times 10^{- 35}$
$6.6 \times 10^{- 21}$

Question

If electron is having a wavelength of 100 A-0- then momentum is -gm  cm  s-1- units6-6times 10-29-6-6times 10-32-6-6times 10-35-6-6times 10-21-

Toppr Admin · Accepted Answer

Momentum -h-x3BB-6-6-xD7-10-x2212-34100-xD7-10-x2212-10-6-6-xD7-10-x2212-26-xA0-kg-xA0-m-s-6-6-xD7-10-x2212-26-xD7-1000-xD7-100-xA0-gm-xA0-cm-s -xA0- -xA0-xA0-x2235- 1kg-1000gm-xA0-1m-100cm-6-6-xD7-10-x2212-21-xA0-gm-xA0-cm-s-xA0-So- the answer is option -D-

If electron is having a wavelength of 100 A0, then momentum is (gm cm s−1) units6.6×10−296.6×10−326.6×10−356.6×10−21

Momentum =hλ=6.6×10−34100×10−10=6.6×10−26 kg m/s=6.6×10−26×1000×100 gm cm/s (∵ 1kg=1000gm 1m=100cm)=6.6×10−21 gm cm/s. So, the answer is option (D).

If electron is having a wavelength of 100 $A^{0}$ , then momentum is $(g m c m s^{- 1})$ units
$6.6 \times 10^{- 29}$
$6.6 \times 10^{- 32}$
$6.6 \times 10^{- 35}$
$6.6 \times 10^{- 21}$

Momentum = $\frac{h}{λ}$

$= \frac{6.6 \times 10^{- 34}}{100 \times 10^{- 10}}$

$= 6.6 \times 10^{- 26} k g m / s$
$= 6.6 \times 10^{- 26} \times 1000 \times 100 g m c m / s$ ( $∵$ 1kg=1000gm 1m=100cm)
$= 6.6 \times 10^{- 21} g m c m / s .$
So, the answer is option (D).