If the values of ∧∞ of NH4Cl,NaOH and NaCl are 130,217 and 109ohm−1⋅cm2⋅equiv−1 respectively, the ∧∞ of NH4OH in ohm−1⋅cm2⋅equiv−1 is:
456
22
238
198
A
22
B
456
C
198
D
238
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Solution
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∧∞(NH4OH)=∧∞(NH4Cl)+∧∞(NaOH)−∧∞(NaCl)
∧∞(NH4OH)=130+217−109
∧∞(NH4OH)=238ohm−1⋅cm2⋅equiv−1
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