In an experiment on photoelectric effect the frequency $v$ of the incident light is plotted against the stopping potential $V_{0}$ . The work function of the photoelectric surface is given by (e is electron charge)

Question

In an experiment on photoelectric effect the frequency

v

of the incident light is plotted against the stopping potential

V_{0}

. The work function of the photoelectric surface is given by (e is electron charge)

Toppr Admin · Accepted Answer

The correct option is A OB-xD7-e-xA0-in-xA0-eVUsing Einstein-apos-s equation -V0-he-x3BD-x2212-W0eComparing this equation with y-mx-c-we get on -x2212-V0- axis-OB-W0ehence- W0-OB-xD7-e-xA0- -xA0- eV-

In an experiment on photoelectric effect the frequency v of the incident light is plotted against the stopping potential V0. The work function of the photoelectric surface is given by (e is electron charge)OB×e in eVOB in voltOA in eVThe slope of the line AB

The correct option is A OB×e in eVUsing Einstein's equation ,V0=heν−W0eComparing this equation with y=mx+c,we get on (−V0) axis,OB=W0ehence, W0=OB×e eV.

The correct option is A $O B \times e i n e V$
Using Einstein's equation ,
$V_{0} = \frac{h}{e} ν - \frac{W_{0}}{e}$

Comparing this equation with $y = m x + c$ ,
we get on $(- V_{0})$ axis,

$O B = \frac{W_{0}}{e}$

hence, $W_{0} = O B \times e$ eV.