In J-J-Thomson-s method - electric field E- magnetic field B and velocity of the electrons were in mutually perpendicular direction- This velocity selector allows particles of velocity to pass undeflected whenv-BEv-B-Ev-E-Bv-B-2-E

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Toppr Admin · Accepted Answer

ElectricForce-EemagneticForce-BveIf both of them act in opposite directions- they may cancel each other in magnitudeEe-Bvev-EB

In J.J.Thomson's method , electric field E, magnetic field B and velocity v of the electrons were in mutually perpendicular direction. This velocity selector allows particles of velocity v to pass undeflected when
$v = B E$
$v = B / E$
$v = E / B$
$v = B^{2} / E$

$E l e c t r i c F o r c e = E e$
$m a g n e t i c F o r c e = B v e$
If both of them act in opposite directions, they may cancel each other in magnitude
$E e = B v e$
$v = \frac{E}{B}$

In J.J.Thomson's method , electric field E, magnetic field B and velocity v of the electrons were in mutually perpendicular direction. This velocity selector allows particles of velocity v to pass undeflected whenv=BEv=B/Ev=E/Bv=B2/E

ElectricForce=EemagneticForce=BveIf both of them act in opposite directions, they may cancel each other in magnitudeEe=Bvev=EB

In J.J.Thomson's method , electric field E, magnetic field B and velocity v of the electrons were in mutually perpendicular direction. This velocity selector allows particles of velocity v to pass undeflected when
$v = B E$
$v = B / E$
$v = E / B$
$v = B^{2} / E$

$E l e c t r i c F o r c e = E e$
$m a g n e t i c F o r c e = B v e$
If both of them act in opposite directions, they may cancel each other in magnitude
$E e = B v e$
$v = \frac{E}{B}$