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Correct options are A) , C) and D)

The De Broglie wavelength of a particle is given by:

$λ=mvh =2Em h $

If the two particles have same velocity, we compare using the equation:

$λ=mvh $ The one with larger mass has a smaller De Broglie wavelength.

Hence option A is correct.

If two particles have the same kinetic energy or fall from the same height (by which they get the same Kinetic energy) we use the second relation:

$λ=2Em h $ In which case the particle with higher mass has a smaller De Broglie wavelength. Hence options C and D are correct.

If the two particles have the same linear momentum, then they have the same wavelength hence option B is wrong.

Thus options A,C,D are correct.

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