Kα wavelength emitted by an atom of atomic number Z=11 is ′λ′. The atomic number for an atom that emits Kα radiation with wavelength 4λ is
6
4
11
44
A
6
B
4
C
11
D
44
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Solution
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Kα corresponds to n=2→n=1 1λ=Z2R(1−1n2) 1λ=121R(1−122) 1λ=121R(34) ---------------(1) 14λ=Z2R(34) ----------(2)
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