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Question

Light of intensity I is incident on a fixed plane surface at an angle 300 with normal to the surface. If 50 % light is reflected and remaining light is absorbed then radiation pressure on the plate is: [Speed of light is c]
  1. 2Ic
  2. 3I8c
  3. I4c
  4. 9I8c

A
2Ic
B
9I8c
C
3I8c
D
I4c
Solution
Verified by Toppr

Intensity of light polarized in the direction 30 to the incident direction=Icos2θ=3I4
Now 3I4×12 is absorbed and 3I4×12 is reflected.
Thus radiation pressure=1c(3I8(3I4))=9I8c

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