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Correct option is C)

where $ϕ=0.5$ eV is the work function of the metal.

Energy of photon $E_{1}=1eV$

$∴$ $21 mv_{1}=1−0.5$

We get $21 mv_{1}=0.5$ eV ....(1)

Energy of photon $E_{2}=2.5eV$

$∴$ $21 mv_{2}=2.5−0.5$

We get $21 mv_{2}=2$ eV ....(2)

Ratio of maximum speeds $v_{2}v_{1} =20.5 =41 $

We get $v_{2}v_{1} =21 $

Solve any question of Dual Nature of Radiation And Matter with:-

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