Light of wavelength 1824A0 , incident on the surface of a metal produces photoelectrons with maximum energy 5.3 eV. Now, when the light of wavelength 1216A0 is used, the maximum energy of photoelectrons is 8.7 eV. The work function of the metallic surface is :
A
6.8 eV
B
1.5 eV
C
13.6 eV
D
3.5 eV
Medium
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Solution
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Correct option is B)
As we know,
E=W0+Kmax. From the given data E is 6.75eV (for λ=1824Ao) or 10.17eV (for λ=1216Ao) ∴W0=E−Kmax=6.75−5.3=1.48eV OR W0=10.17−8.7=1.5eV
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