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>>Photons and Photoelectric Effect
>> $Light of wavelength 1824 A ^0 , incide$

Question

Light of wavelength $1824 A 0$ , incident on the surface of a metal produces photoelectrons with maximum energy 5.3 eV. Now, when the light of wavelength $1216 A 0$ is used, the maximum energy of photoelectrons is 8.7 eV. The work function of the metallic surface is :

A

6.8 eV

B

1.5 eV

C

13.6 eV

D

3.5 eV

Medium

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Solution

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Correct option is B)

As we know,
$E = W_{0} + K_{m a x}$ . From the given data $E$ is $6.75 e V$ (for $λ = 1824 A o$ ) or $10.17 e V$ (for $λ = 1216 A o$ )
$∴ W_{0} = E - K_{m a x} = 6.75 - 5.3 = 1.48 e V$
OR
$W_{0} = 10.17 - 8.7 = 1.5 e V$

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