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Correct option is B)

As per Einstein's Photoelectric equation:

K.E.$_{max}$ = $hν−W$

0.4 = $h×ν−W$ --- (1)

0.9 = $h×1.3ν−W$ --- (2)

(2) - (1)

0.5 = $0.3×hν⇒hν=1.667eV$

Putting this value in equation (1),

$W=1.667−0.4=1.267eV$

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