Question

Photoelectric effect experiments are performed using three different metal plates $p,q$ and $r$ having work functions ${\varphi }_p=2.0eV,{\varphi }_q=2.5eV$ and ${\varphi }_r=3.0eV$, respectively. $A$ light beam containing wavelengths of $550nm,450nm$ and $350nm$ with equal intensities illuminates each of the plates. The correct $I-V$ graph for the experiment is:

(Take $hc=1240eVnm$)

• A.
  
• B.
  
• C.
  
• D.
  

Answer 1

The photoelectric effect can be explain by the following relation:

$e{V}_B=\left[\right(hc/\lambda )-\varphi ]$

$V_B=\left(1/e\right)\left[\right(hc/\lambda )-\varphi ]$