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Einstein's Photoelectric Equation : Energy Quantum of Radiation

Question

Stopping potential $$(V_0)$$ frequency $$(v)$$ of radiation graph for three different emitter surfaces $$A, B$$ and $$C$$ as shown in figure, then
(a) threshold frequency of $$A < B <C$$
(b) work function of $$A < B <C$$
(c) work function of $$A = B = C$$
(d) threshold wavelength of $$A < B <C$$
(e) ratio of the slopes of $$A , B, C$$ id $$1 : 1 : 1$$

A

$$a, b, d$$ are correct

B

$$a, b, d, e$$ are correct

C

$$c, d, e$$ are correct

D

$$a, c, d, e$$ are correct

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Solution

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Correct option is A. $$a, b, d, e$$ are correct

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Similar Questions

Q1

Stopping potential $$(V_0)$$ frequency $$(v)$$ of radiation graph for three different emitter surfaces $$A, B$$ and $$C$$ as shown in figure, then
(a) threshold frequency of $$A < B <C$$
(b) work function of $$A < B <C$$
(c) work function of $$A = B = C$$
(d) threshold wavelength of $$A < B <C$$
(e) ratio of the slopes of $$A , B, C$$ id $$1 : 1 : 1$$

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Q2

For photoelectric effect in a metal, the graph of stopping potential

V_{0} (i n V)

versus frequency

ν (i n Hz)

of the incident radiation as shown in figure. From the graph, find threshold frequency and work function of the metal. (Take

h = 6.6 \times 10^{- 34} J s

)

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Q3

The graph shows variation of stopping potential

V_{0}

versus frequency of incident radiation v for two photosensitive metals A and B. Which of the two metals has higher threshold frequency and why?

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Q4

The work functions for three different metals

A

,

B

and

C

are

φ_{A}

>

φ_{B}

>

φ_{C}

. The graphs between stopping potential

(V_{0})

and frequency of v of incident radiation for them would look like

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Q5

Following graphs show the variation of stopping potential corresponding to the frequency of incident radiation (F) for a given metal. The correct variation is shown in graph (

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