Question

The beam of light has three wavelengths and with a total intensity of equally distributed amongst the three wavelengths. The beam falls normally on the area of a clean metallic surface of work function . Assume that there is no loss of light by reflection and that each energetically capable photon ejects one electron. Calculate the number of photoelectrons liberated in .

A

B

C

D

Hard
BITSAT

Solution

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Correct option is
B

As we know, threshold wavelength
.

Hence, wavelength and will emit electron from the metal surface.
For each wavelength energy incident on the surface per unit time
intensity of each area of the surface wavelength

Therefore, energy incident on the surface for each wavelengths is

Number of photons due to wavelength

Number of photon due to the wavelength

Therefore total number of photoelectrons liberated in ,


.

Solve any question of Dual Nature of Radiation And Matter with:-

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