The capacity of a parallel plate condenser is 5μF.When a glass plate is placed between the plates of the condenser,its potential difference reduces to 1/8 of original value.The magnitude of relative dielectric constant of glass is
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8
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Solution
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The correct option is D 8 Potential of a capacitor without dielectric, V=QC=QdAε0 where
Q is the charge on the capacitor
d is the plate distance
A is the area of plates
ε0 is permeability of free space
After insertion of dielectric,potential becomes:
V′=QC′=QdkAε0 where k is dielectric constant.
since, V′=V8
QdkAε0=Qd8Aε0
k=8
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