The de-Broglie wavelength associated with an electron accelearated to potential difference of V volt is:
V×10−10m
150V×10−8m
√150VA0
150VA0
A
V×10−10m
B
150VA0
C
√150VA0
D
150V×10−8m
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Solution
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12mv2=eV
p=√2meV
λ=hp
=h√2meV
=√150VAo
So, the answer is option (B).
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