The de-Broglie wavelength -lambda- of a particleIs proportional to massIs proportional to impulseIs inversely proportional to impulseDoes not depend on impulse

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Toppr Admin · Accepted Answer

De Broglie wavelength of the particle -x3BB-hmvWe define impulse as the change in the momentum of the particle i-e- I-mvWe get -x3BB-hI-x27F9- -x3BB-x221D-1I

The de-Broglie wavelength ' $λ$ ' of a particle
Is proportional to mass
Is proportional to impulse
Is inversely proportional to impulse
Does not depend on impulse

De Broglie wavelength of the particle $λ = \frac{h}{m v}$
We define impulse as the change in the momentum of the particle i.e. $I = m v$
We get $λ = \frac{h}{I}$
$⟹$ $λ \propto \frac{1}{I}$

The de-Broglie wavelength 'λ' of a particleIs proportional to massIs proportional to impulseIs inversely proportional to impulseDoes not depend on impulse

De Broglie wavelength of the particle λ=hmvWe define impulse as the change in the momentum of the particle i.e. I=mvWe get λ=hI⟹ λ∝1I

The de-Broglie wavelength ' $λ$ ' of a particle
Is proportional to mass
Is proportional to impulse
Is inversely proportional to impulse
Does not depend on impulse

De Broglie wavelength of the particle $λ = \frac{h}{m v}$
We define impulse as the change in the momentum of the particle i.e. $I = m v$
We get $λ = \frac{h}{I}$
$⟹$ $λ \propto \frac{1}{I}$