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Question

The de-Broglie wavelength of a particle moving with a velocity 2.25×108 m/s is equal to the wavelength of photon. The ratio of kinetic energy of the particle to the energy of the photon is :
  1. 18
  2. 38
  3. 58
  4. 78

A
18
B
78
C
38
D
58
Solution
Verified by Toppr

Kparticle=12mv2 also λ=hmv
Kparticle=12(hλv).v2=vh2λ ...(i)
Kphoton=hcλ ....(ii)
KparticleKphoton=v2c=2.25×1082×3×108=38

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