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Standard XII
Physics
Question
The energy that should be added to an electron to reduce its de broglie wavelength from 1 nm to 0.5 nm is
Four times the initial energy.
Equal to initial energy.
Twice the initial energy.
Thrice the initial energy.
A
Equal to initial energy.
B
Twice the initial energy.
C
Thrice the initial energy.
D
Four times the initial energy.
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Solution
Verified by Toppr
λ
=
h
p
=
h
√
2
m
(
K
E
)
∴
New energy should be 4 times and hence energy to be added is thrice the initial energy.
So, the answer is option (D).
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