0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

The maximum kinetic energy (Ek) of emitted photoelectrons against frequency ν of incident radiation is plotted as shown in fig. The slope of the graph is equal to
20745.png
  1. Charge on electron
  2. Work function of emitter
  3. Plancks constant
  4. Ratio of Plancks constant and charge on electron

A
Charge on electron
B
Work function of emitter
C
Ratio of Plancks constant and charge on electron
D
Plancks constant
Solution
Verified by Toppr

Answer is C.
Ek=hνϕ
So, comparing it with
y=mx+c
we get slope =h

Was this answer helpful?
2
Similar Questions
Q1
The maximum kinetic energy (Ek) of emitted photoelectrons against frequency ν of incident radiation is plotted as shown in fig. The slope of the graph is equal to
20745.png
View Solution
Q2
When a high frequency electromagnetic radiation is incident on a metallic surface, electrons are emitted from the surface. Energy of emitted photoelectrons depends only on the frequency of incident electromagnetic radiation and the number of emitted electrons depends only on the intensity of incident light.
Einstein's photoelectric equation [Kmax=hνϕ] correctly explains the PE, where ν= frequency of incident light and ϕ= work function.
The slope of the graph shown in fig. [here h is the Planck's constant and e is the charge of an electron] is

View Solution
Q3
In a photoelectric experiment, the kinetic energy of photoelectrons was plotted against the frequency of the incident radiation (ν), as shown in the figure. Which of the following statements is correct?

View Solution
Q4
The maximum kinetic energy of the emitted frequency v of incident radiation is plotted as shown in fig. This graph help us in determining the following physical quantities
163812_3278c092f8374f50ae38b66ddcd5ec56.png
View Solution
Q5
Radiation of frequency ν is incident on photosensitive metal. Maximum kinetic energy of the photoelectrons is E. If the frequency of incident radiation is doubled, find out the maximum kinetic energy of photoelectrons.

View Solution