The necessary condition photoelectric emission is -displaystyle hnu hnu-0-displaystyle E-k- - hnu-0-displaystyle E-r- - hnu-0-

Question

The necessary condition photoelectric emission is -displaystyle hnu  hnu-0-displaystyle E-k- - hnu-0-displaystyle E-r- - hnu-0-

Toppr Admin · Accepted Answer

Light with frequencies below a certain cutoff value- called the threshold frequency- would not eject photoelectrons from the metal surface no matter how bright the source is-Hence h-x3BD-gt-h-x3BD-o

The necessary condition for photoelectric emission is :
$h ν < h ν_{0}$
$h ν > h ν_{0}$
$E_{k} > h ν_{0}$
$E_{r} < h ν_{0}$

Light with frequencies below a certain cutoff value, called the threshold frequency, would not eject photoelectrons from the metal surface no matter how bright the source is.
Hence $h ν > h ν_{o}$

The necessary condition for photoelectric emission is :hν<hν0hν>hν0Ek>hν0Er<hν0

Light with frequencies below a certain cutoff value, called the threshold frequency, would not eject photoelectrons from the metal surface no matter how bright the source is.Hence hν>hνo

The necessary condition for photoelectric emission is :
$h ν < h ν_{0}$
$h ν > h ν_{0}$
$E_{k} > h ν_{0}$
$E_{r} < h ν_{0}$

Light with frequencies below a certain cutoff value, called the threshold frequency, would not eject photoelectrons from the metal surface no matter how bright the source is.
Hence $h ν > h ν_{o}$