The photo-electric threshold wavelength for a metal is 6620 $A^{o}$ . Its work function is (given $h = 6.62 \times 10^{- 34} J s, c = 3 \times 10^{8}$ m/s)

Question

The photo-electric threshold wavelength a metal is 6620 A-o- Its work is -given h - 6-62 times 10-34- Js- c - 3 times 10-8- m-s-1-87 eV2-00 eV3-00 eV2-87 eV

Toppr Admin · Accepted Answer

-x3D5-hc-x3BB-T-1240662-xA0-xA0-xA0-hc-1240eV-x2212-nm-1-87eVSo- the answer is option -A-

The photo-electric threshold wavelength for a metal is 6620 $A^{o}$ . Its work function is (given $h = 6.62 \times 10^{- 34} J s, c = 3 \times 10^{8}$ m/s)
1.87 eV
2.00 eV
3.00 eV
2.87 eV

$ϕ = \frac{h c}{λ_{T}}$

$= \frac{1240}{662} (h c = 1240 e V - n m)$

$= 1.87 e V$
So, the answer is option (A).

The photo-electric threshold wavelength for a metal is 6620 Ao. Its work function is (given h=6.62×10−34Js,c=3×108 m/s)1.87 eV2.00 eV3.00 eV2.87 eV

ϕ=hcλT=1240662 (hc=1240eV−nm)=1.87eVSo, the answer is option (A).

The photo-electric threshold wavelength for a metal is 6620 $A^{o}$ . Its work function is (given $h = 6.62 \times 10^{- 34} J s, c = 3 \times 10^{8}$ m/s)
1.87 eV
2.00 eV
3.00 eV
2.87 eV

$ϕ = \frac{h c}{λ_{T}}$

$= \frac{1240}{662} (h c = 1240 e V - n m)$

$= 1.87 e V$
So, the answer is option (A).