The position x of a particle varies with time as x=at2−bt3. The acceleration of particle is zero at time T equal to
ab
2a3b
a3b
Zero
A
a3b
B
Zero
C
ab
D
2a3b
Open in App
Solution
Verified by Toppr
x=at2−bt3
⇒ Velocity =dxdt=2at−3bt2
Acceleration=d2xdt2=ddt(2at−3b2)=2a−6bt
or a=2a−6bt
Making a=0
⇒2a=6bt
⇒t=dfrac2a6b=a3b.
Was this answer helpful?
54
Similar Questions
Q1
The position x of a particle varies with time as x=at2−bt3. The acceleration of particle is zero at time T equal to
View Solution
Q2
The position x of a particle varies with time (t) as x=at2−bt3. The acceleration of the particle will be equal to zero, at time
View Solution
Q3
The position x of a particle varies with time (t) as x=at2−bt3. The acceleration at time t of the particle will be equal to zero, where t is equal to
View Solution
Q4
The position x of a particle varies with time t, as x=At2−Bt3. The acceleration at time t of the particle will be equal to zero. What is the value of t?
View Solution
Q5
The position x of a particle varies with time (t) as
x = at2 - bt3
The acceleration of the particle will be zero at time