The radiation is emitted when a hydrogen atom goes from a higher energy state to eluga energy state. The wavelength of one line in visible region of atomic spectrum of hydrogen is 6.63∗10−7m. Energy difference between the two state is
3.0∗10−19J
1.0∗10−18J
5.0∗10−10J
6.5∗10−7J
A
5.0∗10−10J
B
1.0∗10−18J
C
6.5∗10−7J
D
3.0∗10−19J
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Solution
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λ=6.63×10−7m
ΔE=hν=hcλ
⇒ΔE=6.6×10−34×3×1086.63×10−7
⇒ΔE=3.0×10−19J
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